In a triangle ABC, ANGLE A = 90 DEGREE , ANGLE C = 55 DEGREE , AD PERPENDICULAR ON BC , THEN VALUE OF ANGLE BAD IS
simi:
the value of angle BAD is 55
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Answered by
8
the value of angle ABC=90-55=35
so the value of angle BAD is 90-35=55
so the value of angle BAD is 90-35=55
Answered by
16
first the ΔABC is a right angled triangle as the angle BAC is a 90⁰
now, in ΔABC angle A= 90⁰-------------(GIVEN)
angle C= 55⁰----------------------------------(GIVEN)
therefore, angle B= (angle A - angle B)-----(REMAINING ANGLES)
angle B=(90-55)
angle B=35------------------(1)
now in ΔBDA
in ΔBDA, angle D=90⁰---------------(GIVEN)
also, angle B=35⁰--------------(FROM 1)
therefore,angle A=(angle D-angle B)-------(REMAINING ANGLES)
angle A=(90-35)
angle A=55
therefor, angle A=55⁰.
now, in ΔABC angle A= 90⁰-------------(GIVEN)
angle C= 55⁰----------------------------------(GIVEN)
therefore, angle B= (angle A - angle B)-----(REMAINING ANGLES)
angle B=(90-55)
angle B=35------------------(1)
now in ΔBDA
in ΔBDA, angle D=90⁰---------------(GIVEN)
also, angle B=35⁰--------------(FROM 1)
therefore,angle A=(angle D-angle B)-------(REMAINING ANGLES)
angle A=(90-35)
angle A=55
therefor, angle A=55⁰.
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