Math, asked by debanti, 1 year ago

In a triangle  ABC, ANGLE  A = 90 DEGREE ,  ANGLE C = 55 DEGREE , AD  PERPENDICULAR ON BC , THEN VALUE OF  ANGLE  BAD IS


simi: the value of angle BAD is 55
KNREDDY129: VALUE=55 ALTERNATE INTERIOR ANGLES
hariprasathrock: the value of angle BAD is45

Answers

Answered by nicey
8
the value of angle ABC=90-55=35
so the value of  angle BAD is 90-35=55

debanti: HOW ?
Answered by yoyoyogesh
16
first the ΔABC is a right angled triangle as the angle BAC is a 90⁰
now, in ΔABC angle A= 90⁰-------------(GIVEN)
angle C= 55⁰----------------------------------(GIVEN)
therefore, angle B= (angle A - angle B)-----(REMAINING ANGLES)
               angle B=(90-55)
               angle B=35------------------(1)
now in ΔBDA
      in ΔBDA, angle D=90⁰---------------(GIVEN)
             also, angle B=35⁰--------------(FROM 1)
therefore,angle A=(angle D-angle B)-------(REMAINING ANGLES)
             angle A=(90-35)
             angle A=55
therefor, angle A=55⁰.
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