Question

in a triangle ABC, angle a + angle b= 100 and angle b + angle c =135 , find angle a ,angle b and angle c

Answer 1

Answer:

a=45°; b=55°;c=80°

Step-by-step explanation:

Here, given a+b=100° and b+c=135°

a+b=100                ;        b+c=135

=>a = 100 - b              =>c=135-b

(Sum of all the angles of a triangle is 180°)

so,       a + b +c = 180°           (substituting values of a and c)    

      => (100-b)+b+(135-b)=180°

      =>100-b+b+135-b=180°         (here, -b & +b get cancelled)

      => -b=180°-235°

      => b=55°

Therefore, using the value of 'b' 'a' and 'c' can be found

   a=100-b                 ;        c=135-b

=>a=100-55                     =>c=135-55

=>a=45°                           =>c=80°

Therefore, a=45°; b=55°;c=80°

Hope it helps you:)