in a triangle ABC ,
ANGLE A + ANGLE B = 105 DEGREE
ANGLE B + ANGLE C = 120 DEGREE
find B.
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Answered by
105
Hi ,
In a triangle sum of the three angles
is equal to 180°.
In triangle ABC ,
A + B + C = 180° -----( 1 )
A + B = 105
A = 105 - B ----( 2 )
B + C = 120°
C = 120 - B -----( 3 )
Put ( 2 ) and ( 3 ) in equation ( 1 ) ,
105 - B + B + 120 - B = 180
225 - B = 180
- B = 180 - 225
-B = -45
Therefore ,
B = 45°
I hope this helps you.
:)
In a triangle sum of the three angles
is equal to 180°.
In triangle ABC ,
A + B + C = 180° -----( 1 )
A + B = 105
A = 105 - B ----( 2 )
B + C = 120°
C = 120 - B -----( 3 )
Put ( 2 ) and ( 3 ) in equation ( 1 ) ,
105 - B + B + 120 - B = 180
225 - B = 180
- B = 180 - 225
-B = -45
Therefore ,
B = 45°
I hope this helps you.
:)
Answered by
30
In this triangle,
C + B = 120°.............(i) &
A + B = 105°.............(ii)
We know that in any triangle, A + B + C = 180°.......(iii)
Now, we get from equation (i),(ii),(iii)
A+B+C+B-A-B-C = 120° + 105° - 180°
or, B = 45°
I hope you enjoyed
C + B = 120°.............(i) &
A + B = 105°.............(ii)
We know that in any triangle, A + B + C = 180°.......(iii)
Now, we get from equation (i),(ii),(iii)
A+B+C+B-A-B-C = 120° + 105° - 180°
or, B = 45°
I hope you enjoyed
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