Question

In a triangle ABC angle A + angle B= 1080

and angle B + angle

C = 1300 find angles A, B and C.​

Answer 1

Answer:

Angle A = 50°

Angle A = 50°Angle B = 58°

Angle A = 50°Angle B = 58°Angle C = 72°

Step-by-step explanation:

Here, A+B = 108°

Here, A+B = 108°and B+C = 130°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°Therefore, A+B+C = 180°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°Therefore, A+B+C = 180°=> C = 180°-108°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°Therefore, A+B+C = 180°=> C = 180°-108°=> C = 72°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°Therefore, A+B+C = 180°=> C = 180°-108°=> C = 72°So, B = 130°-72° = 58°

Here, A+B = 108°and B+C = 130°We know that in a triangle sum of interior angles is 180°Therefore, A+B+C = 180°=> C = 180°-108°=> C = 72°So, B = 130°-72° = 58°And, A = 108°-58° = 50°

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