Question

In a triangle ABC, angle A+angle B=110°, angle C+angle A=135°.Find the value of angles of∆ABC
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Answer 1

as we know that the sum of angles of a triangle is 180 here,

angle A + angle B =110

angle A + angle C= 135

now,

180 = (angle A + angle B) - angle A + (angle A + angle C)

180= 110 + 135 - angle A 

180 - 110 - 135 = angle A 

180-245 = - angle A

- 65 = - angle A

65= angle A

Answer 2

Answer:

Angle a = 65° , Angle b = 45° , Angle c = 70°

Step-by-step explanation:

In ∆ABC

Angle A + Angle B + Angle C = 180

110 + Angle c = 180

Angle c = 70°

Angle c + Angle a =135

Angle a = 135-70

Angle a = 65

Angle b = 110-65

Angle b = 45