In a triangle ABC , angle A - angle B = 20 angle B - angle C =32 ,Then the angle A is
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in a triangle ABC, it is given that
A - B = 20
⇒B = A - 20
B - C = 32
⇒ C = B-32 = (A-20)-32 = A-52
we know that A+B+C=180
⇒A + (A-20) + (A-52) = 180
⇒3A -20-52 = 180
⇒3A = 180+20+52
⇒3A = 252
⇒ A = 252/3 = 84°
⇒ A = 84°
A - B = 20
⇒B = A - 20
B - C = 32
⇒ C = B-32 = (A-20)-32 = A-52
we know that A+B+C=180
⇒A + (A-20) + (A-52) = 180
⇒3A -20-52 = 180
⇒3A = 180+20+52
⇒3A = 252
⇒ A = 252/3 = 84°
⇒ A = 84°
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