In a triangle ABC , angle A+ angle B= 65 degrees and angle B+ angle C= 140 degrees. Find the angles.
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∠A+ ∠B= 65° → 1
∠B+∠C= 140°→2
1 + 2
∠A+ 2∠B+ ∠C = 205° →3
WE KNOW, ∠A+ ∠B + ∠C = 180° →4
SUBTRACT 4 FROM 3
WE GET, ∠B= 25°
THEREFORE
∠A=40°
∠C= 115°
HOPE SO IT WILL HELP......
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