Question

In a triangle abc angle a +b=110 angle c+a=135 then find angle a

Answer 1

I think you understand.

Answer 2

Answer:

a+b=110°

c+a=135°

we know that

a+b+c=180°

110°+c=180°

c=70°

given, c+a=135°

70°+a=135°   [c=70°]

a=135°-70°

a=65°

so,b+a=110°

b+65°=110° [a=65°]

b=110°-65°

b=45°

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