Question

In a triangle ABC, angle A is 12° more than measure of angle C & angle B is 4 times the measure of angle C, the measure of each angle is:



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Answer 1

★ Answer ★

Let ∠C in ∆ABC is x°.

Then ATQ, ∠A = (12 + x)°

∠B = (4x)°

As we know that the sum of the three angles of a triangle is always 180°.

∴ ∠A + ∠B + ∠C = 180°

» (12 + x) + (4x) + (x) = 180

» 6x + 12 = 180

» 6x = 180 - 12

» x = 168/6

» x = 28° = ∠C

So, ∠A = 12 + x = 12 + 28 = 40°

∠B = 4x = 4(28) = 112°

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CreativeAB

• The Genius •