In a triangle ABC, angle A is 25 degree more than angle B and angle C is 10 degree less than angle B. Find the angles.
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Let angle B be x.
According to the question -
Angle A = Angle B + 25°
= x + 25°
Angle C = Angle B - 10°
= x - 10°
Angle A + Angle B + Angle C = 180° ( Angle sum property of a triangle)
=> (x + 25°) + (x) + ( x-10°) = 180°
=> 3x + 15° = 180°
=> 3x = 165°
=> x = 165° /3
=> x = 55°
Therefore, angle B = 55°
Angle A = x + 25°
= 55° + 25°
= 80°
Angle C = x - 10°
= 55° - 10°
= 45°
Ans.= Angle A = 80° , Angle B = 55° and Angle C = 45°.
Hope it helps!! ^^
According to the question -
Angle A = Angle B + 25°
= x + 25°
Angle C = Angle B - 10°
= x - 10°
Angle A + Angle B + Angle C = 180° ( Angle sum property of a triangle)
=> (x + 25°) + (x) + ( x-10°) = 180°
=> 3x + 15° = 180°
=> 3x = 165°
=> x = 165° /3
=> x = 55°
Therefore, angle B = 55°
Angle A = x + 25°
= 55° + 25°
= 80°
Angle C = x - 10°
= 55° - 10°
= 45°
Ans.= Angle A = 80° , Angle B = 55° and Angle C = 45°.
Hope it helps!! ^^
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