in a triangle abc, angle A is 25 degrees more than Angle B and angle C is 10 degrees then Angle B what are the angles of the triangle
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Answered by
26
let angle b will be = x°
then angle a = x+25
and angle c= x-10
now angle a +b+c= 180
x+25+x+x-10=180
3x+15=180
3x=180-15
3x=165
x=165/3
x=. 55
now angle a=x+25
55+25=80
and angle b=55
angle c= x-10
55-10=45
then angle a = x+25
and angle c= x-10
now angle a +b+c= 180
x+25+x+x-10=180
3x+15=180
3x=180-15
3x=165
x=165/3
x=. 55
now angle a=x+25
55+25=80
and angle b=55
angle c= x-10
55-10=45
Answered by
16
let the angle b= x degree, a=25+x,c=10-x
we know that,
sum of all angle in triangle =180degree
x+25+x+10-x=180
3x+15=180
x=180-15
x=165/3
x=55
a=80°
b=55
c=45
we know that,
sum of all angle in triangle =180degree
x+25+x+10-x=180
3x+15=180
x=180-15
x=165/3
x=55
a=80°
b=55
c=45
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