In a triangle abc angle a is 50degree and a triangle is made inside of abc triangle obc in which angle bo and angle co are the bisector of angle b and angle c then find angle boc .
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Answer:
Angle BOC = 120
PROOF
Angle A + Angle B + Angle C = 180
So, Angle B + Angle C = 120 ( angle A = 60)
Now 1/2 (Angle B + Angle C) = 60
1/2 angle B + 1/2 angle C =60………. I
In triangle BOC
1/2 angle B + 1/2 angle C + Angle BOC = 180
(BO and CO are angle bisectors)
Or 60 + Angle BOC = 180 (Using I)
OR ANGLE BOC = 120
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