Question

In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ?
A) 138 to 164
B) 125 to 147
C) 148 to 158
D) 152 to 164

Answer 1

$\bf\huge\color{red}{SOLUTION;}$

A+7B=112

it is clear that A = 14, then it becomes A>=B, but A is smallest angle) given
so, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)
so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)
so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)

Answer 2

In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ?
A) 138 to 164
B) 125 to 147✔✔
C) 148 to 158
D) 152 to 164

A + 7B = 112
C = A + 7B
= 125 to 147