In a triangle ABC, angle A is the vertex angle=70, angle ABC =54. If BO and OC are the bisectors of angle ABC and ACB respectively of Triangle ABC, find angle BOC.
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Answer:
angle BOC = 125°
Step-by-step explanation:
In triangle ABC we have
angle A + angle ABC + angle ACB = 180° ( since sum of all angles is 180°)
70° + 54°+ angle ACB = 180°
angle ACB = 56°
now angle ABC = angle ABO + angle OBC
angle ABO = angle OBC = 54/2=27°
now angle ACB = angle ACO + angle OCB
angle ACO = angle OCB = 56/2 = 28°
in triangle BOC
angle OBC + angle OCB + angle BOC = 180°
27° + 28° + angle BOC = 180°
angle BOC = 125°
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