Question

in a triangle abc,angle a is twice angleb,then a^2-b^2=​

Answer 1

Answer:

${3b}^{2}$

Step-by-step explanation:

angle a = 2× angle b

${a}^{2} - {b}^{2} = \\ {(2b)}^{2} - {b}^{2} \\ 4 {b}^{2} - {b }^{2} \\ 3 {b}^{2}$