In a triangle ABC, angle a is x degree, angle b is (3x-2) degree and angle c is y degree. Also angle c - angle b = 9 degree. Find all the 3 angles of the triangle ABC.
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we know that sum of angles in triangle
a+b+c = 180 degree........(i)
a=x, b= 3x-2, c=y
so put in(i)
x+3x-2+y= 180
y+4x-2=180........(ii)
also, c-b =9 degree
y-3x+2=9.........(iii)
subtract (ii)- (iii), we get
7x-4=171 degree
7x=175
x=25
hence, a=25
b= 3x-2
b= 3*25-2
b=75-2= 73
also
y-3x+2=9
y= 9-2+3x
y= 9-2+3*25
y=7+75
y= 82=c
a=25, b=73, c= 82
a+b+c = 180 degree........(i)
a=x, b= 3x-2, c=y
so put in(i)
x+3x-2+y= 180
y+4x-2=180........(ii)
also, c-b =9 degree
y-3x+2=9.........(iii)
subtract (ii)- (iii), we get
7x-4=171 degree
7x=175
x=25
hence, a=25
b= 3x-2
b= 3*25-2
b=75-2= 73
also
y-3x+2=9
y= 9-2+3x
y= 9-2+3*25
y=7+75
y= 82=c
a=25, b=73, c= 82
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