in a triangle abc angle A minus angle b equal to 33 and Angle B minus angle c equal to 18 find the measures of each angles
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Answered by
100
A-B=33°
i.e A= 33+B
B-C=18°
B-18=C
we know that A+B+C= 180°
33+B+B+B-18=180
3B+15=180
3B=180-15
3B=165
B=165/3
B=55°
A=33+55=88°
C=55-18=37°
i.e A= 33+B
B-C=18°
B-18=C
we know that A+B+C= 180°
33+B+B+B-18=180
3B+15=180
3B=180-15
3B=165
B=165/3
B=55°
A=33+55=88°
C=55-18=37°
shyam26:
thanks
Answered by
40
A-B=33°
i.e A= 33+B
B-C=18°
B-18=C
we know that A+B+C= 180°
33+B+B+B-18=180
3B+15=180
3B=180-15
3B=165
B=165/3
B=55°
A=33+55=88°
C=55-18=37°
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