Question

In a triangle ABC,angle ABC =100°, angle ACB =35° and BD is perpendicular to AC and meets the side AC at D. If BD=2 cm , find the angle CAB and length AD.
$\sqrt{a} = \sqrt{b} + \sqrt{c}$
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Answer 1

Answer:

angle of CAB is 45°

length of AD is 2cm

angle CAB=180°-(100°+35°)=45°

For the length of AD

Triangle BDA, B=(100/2)° D=90° A=45°

Therefore, AD=BD=2cm

as, tan 45°=1