Question

In a triangle ABC,angle AC greater than AB and the bisector of angleA meets BC at D then angle ABC isWhich angle

Answer 1

ANSWER

In △,s ABD and ACD,

∠BAD=∠CAD (AD is the bisector of angle A)

AD=AD .... (common)

AB=AC .... (given)

Thus, △ABD≅△ACD

Hence, ∠ADC=∠ADB=x (Corresponding angles of congruent triangles)

Sum of angles, ∠ADC+∠ADB=180 (Angles on a straight line)

⇒2x=180

⇒x=90

∘

⇒∠ADC=∠ADB=90

∘

Thus, AD⊥BC

solution