In A triangle ABC angle ACB = 90°, BC is to produced to D such that angleDAB = 90°.
Prove that AB square = BC×BD.
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Step-by-step explanation:
comparing ΔABC and ΔABD
∠ACB = ∠DAB = 90° .............1st angle
∠ABC = ∠ABD = ∠B ..................2nd angle
∠BAC = ∠ADB ........third angle will be equal too as the sum of three angle is same (180°)
So, ΔABC and ΔABD are similar and their similar sides will be proportional also.
Now, AB×AB = BC×BD
OR, AB² = BC×BD
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