Question

In a triangle abc , angle b=45,angle c =55 ,and bisector of angle a meets bc at point d .find angle adb and angle adc ​

Answer 1

Answer:

GIVEN ==> ∠B = 45, ∠C = 55

So,

∠A = 180° − 45° − 55°

= 180° - 100°

= 80°

From △ABD,

40° + 45° + ∠ADB = 180°

==> 85° + ∠ADB = 180°

==> ∠ADB = 180 - 85

==> ∠ADB = 95°

From △ADC,

40° + 55° + ∠ADC = 180°

==> 95° + ∠ADC = 180°

==> ∠ADC = 180 - 95

==> ∠ADC = 85°

hEnCe, ∠ADB = 95° aNd ∠ADC = 85°