Question

in a triangle abc , angle b = 45° and angle c=55°, AD Bisects angle a .find angle ADB and angle ADC

Answer 1

angle a + angle b + angle c = 180 (angle sum property)

a + 45+55= 180

a + 100 = 180

a = 180-100

a= 80

AD bisects angle a

i.e angle ADB= angle ADC

angle ADB + angle ADC = 80

angle ADB + angle ADB =80

2angleADB= 80

angle ADB = 80/2

angle ADB = 40

angle ADB = angle ADC

40 = angle ADC

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Answer 2

Please mark as the brainliest if it is helpful and it took a lot of effort to do this...