Question

In a triangle ABC, angle B=80 degrees, angle C=20 degrees. A line is drawn to any point D on BC.Such that AB=CD, Find the measure of angle BDA​

Answer 1

$\red{A}\pink{N}\orange{S}\green{W}\blue{E}\gray{R}$

Answer: Measure of angle BDA is 60 degrees

Solution:

angle B=80° and angleC=20°

bullet angle A+ angle B+ angle C=180° Angle sum property of triangle)

angle A+80+20=180°

angle A=80°

Now, lets say that AD is such that it is angle bisector of angle A

angle BAD=80/2=40°

bullet angle BAD+ angle B+ angle BDA=180° (Angle sum property of triangle)

bullet angle BDA=60°

40+80+ angle BDA=180°

Answer 2

Answer:

Answer: Measure of angle BDA is 60 degrees

Solution:

angle B=80° and angleC=20°

bullet angle A+ angle B+ angle C=180° Angle sum property of triangle)

angle A+80+20=180°

angle A=80°

Now, lets say that AD is such that it is angle bisector of angle A

angle BAD=80/2=40°

bullet angle BAD+ angle B+ angle BDA=180° (Angle sum property of triangle)

bullet angle BDA=60°

40+80+ angle BDA=180°