In a triangle abc , angle b is greater than angle
a. if the values of angle a and angle b is equal to 3sinx-4sin^3x-k=0,0
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3sinx - 4sin3x + k = 0
sin3x =-k
since 0<k<1
so -1<sin3x<0 ...............1
A and B are angel of triangle so
0< A,B,A+B<∏
0<3A,3B<3∏
from equation 1
∏ <3A,3B <2∏
A and B angel satisfied the equation 1 then
A+B =∏
so angel C=0 which is not possible in a triangle.
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