Question

In a triangle ABC, angle bisector of interior angle B and
exterior angle C intersect at P. If angle A=70° .
find angle BPC .

Answer 1

Answer:

∠BPC =125

Step-by-step explanation:

For the sake of simplicity, I am not gonna put this symbol °, just pretend they are there. Also, you didn't quite present any visual information, so this answer is only correct if I am imagine the diagram the way you have it.

Let ∠PBC be x

     ∠PCB be y

∠ABC + ∠ACB

= 180-70 (∠s sum of Δ )

=110

∵ The bisector of x and y intersect at P. {Meaning x is half of ∠ABC and y is half of  ∠ACB .}

x + y = 110 ÷ 2

        = 55

∠ BPC = 180 -55 (∠s sum of Δ )

           = 125

Hmm, when i started i thought having the x and y would be easier now looking at it, the doesn't really make a difference. so ¯\_(ツ)_/ Hope it helps.