Question

In a triangle ABC, angle C = 3, angle B= 2 (A+B). Find the three angles.class10

Answer 1

let <C=3<B=2<(A+B)=x

<C=x, -----(1)
3<B=x
<B=x/3----(2)
2<(A+B)=x
<A+<B=x/2
<A=x/2 -<B
<A=x/2-x/3-----(3)
sum of the three angles in a triangle is 180degree
<A+<B+<C=180
x/2-x/3+x/3+x=180[from(1),(2),(3)]
(3x-2x+2x+6x)/6=180
9x/6=180
x=180*6/9
x=20*6
x=120

therefore
A= x/2-x/3=120/2-120/3=60-40=20
B=x/3=120/3=40
C=x=120

Answer 2

here is your correct answer