In a triangle ABC angle C= 3angle B= 2(angle A+ angle B) find the three angles
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according to question
C=3B=2 (A+B)=k (let)
C=k
B=k/3
A=k/2-k/3=k/6
now
A+B+C=180 {according to triangle property)
k+k/3+k/6=180
3k/2=180
k=120
hence C=120
B=40
A=20
C=3B=2 (A+B)=k (let)
C=k
B=k/3
A=k/2-k/3=k/6
now
A+B+C=180 {according to triangle property)
k+k/3+k/6=180
3k/2=180
k=120
hence C=120
B=40
A=20
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