in a triangle abc angle C = angle A, AC-AB=3cm and its perimeter is 15 cm. Find AC.
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Given. Angle C= angle A.
So AB=BC( opposite sides equal to equal Opposite angles..)
Given AC-AB=3Cm.
And Perimeter =15cm.
Now Perimeter=AC+AB+BC.
→15=AC+BC+AB.
→15=AC+BC+(AC-3) [Since AC-AB=3→AC=3+AB→AB=AC-3]
→15=AC+AB+AC-3(AB=BC)
→15+3=2AC+(AC-3)
→18+3=3AC
→21=3AC
→AC=21/3
→AC=7Cm
Hope It helps
Regards,
Leukonov.
So AB=BC( opposite sides equal to equal Opposite angles..)
Given AC-AB=3Cm.
And Perimeter =15cm.
Now Perimeter=AC+AB+BC.
→15=AC+BC+AB.
→15=AC+BC+(AC-3) [Since AC-AB=3→AC=3+AB→AB=AC-3]
→15=AC+AB+AC-3(AB=BC)
→15+3=2AC+(AC-3)
→18+3=3AC
→21=3AC
→AC=21/3
→AC=7Cm
Hope It helps
Regards,
Leukonov.
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I will explain with help of photo
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