in a triangle abc angle C is equal to angle A C minus a b is equal 3 cm and its perimeter is 15 cm find AC
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Given, <A=<C AC-AB=3
AB=BC. AC=3+AB
Perimeter of ∆ABC=15cm.
AB+BC+CA=15cm
AB+BC+3+AB=15cm(AB=3+AB)
AB+AB+3+AB=15cm(AB=BC)
3AB=15-3
3AB=12
AB=12/3
AB=4cm
=AC=3+AB
3+4
7cm Ans
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