Question

in a triangle ABC angle C is three times angle B. also angle C is two times the sum of the other two angle. find each angle. ​

Answer 1

Step-by-step explanation:

Let ABC be 3 angles of a triangle ABC.

Then,

C = 3 B .... (1)

C = 2(A+B) ....(2)

Equate equation (1) &(2)

3 B = 2(A+B)

3B = 2A + 2B

B = 2 A

B/2 = A

Sum of angles of triangles is 180

<A + <B + <C = 180

B/2 + B +3B = 180

B + 2B +6B /2 = 180

9B /2 = 180

B/2 = 180/9

B /2 = 20

B = 40

Therefore, <A = 40/2 =20

<B = 40

<C = 3(40)= 120

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