Question

In a triangle ABC angleA=3B=6 angle C find all angles of the triangle

Answer 1

A = 3B = 6C
So,
By angle sum property
A+B+C = 180
6(A+B+C) = 6*180
6A+6B+6C = 1080.
6*(6C) + 2*3B + 6C = 1080.
36C + 2*6C + 6C = 1080.
54C = 1080.
C = 20°
So,
A = 6C = 6*20 = 120°
3B = 6C
B = 6C / 3
B = 2C
B = 2*20 = 40°

Therefore,
A = 120°
B = 40°
and
C = 20°.

Answer 2

Given that ∠A = 3∠B

& ∠ B =2∠C

Now,

Let ∠C be x

So,

∠A + ∠B + ∠C =180°

=> 6x + 3x + x = 180°

=> 10x = 180°

So,

x = 18°

∴ ∠A = 6×18=108°

∠B = 3×18=54°

∠C = 18°

$................ans$

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