In a triangle ABC
angleA=angle B = 65°. The smallest side of the triangle ABC
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GIVEN :
- IN ΔABC ∠A = ∠B = 65°
TO FIND :
- SMALLEST SIDE OF TRIANGLE
SOLUTION :
∠A + ∠B + ∠C = 180°
=> 65° + 65° + ∠C = 180°
=> 130° + ∠C = 180° => ∠C = 50°
THE SIDE WHICH IS OPPOSITE TO THE ∠C BECOMES THE SMALLEST SIDE BECAUSE ∠C IS THE ANGLE WITH SMALLER MEASURE { ∵ FROM THEOREM }
THE SIDE OPPOSITE TO ∠C IS AB
∴ AB BECOMES THE SHORTEST SIDE OF THE TRIANGLE
HOPE IT HELPS !!!
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