In a triangle ABC angleA = x°, angleB = 3x-2°, angleC = y° and angleC - angleB = 9°. Find the four angles.
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Step-by-step explanation:
Ina△ABC, (By angle sum property)
∠A+∠B+∠C=180
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∠C−∠B=9
⟹y−(3x−2)=9
∴y=7+3x
x+(3x−2)+y=180
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⟹4x−2+7+3x=180
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⟹x=25
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∴y=7+3×25=82
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∴∠A=x=25
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,B=3x−2=73
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∠C=y=82
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