In a triangle ABC, angleB=90°. If AB=BC, find the value of cosec C and cot C
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cosec c=√2 ,cot c =1
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cosec c value is 2 cot c value is 1
take AB and BC is x and take hypotenuse as 2x
Ac sq. = AB sq.+ BC sq
2x sq = xsq.+xsq
2xsq.= 2xsq.
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