Math, asked by ananyanand1309, 6 months ago

in a triangle ABC, angleB > angleC. if AM is the bisector of angleBAC and AN is perpendicular to BC. prove that angleMAN = 1/2(angleB - angleC).

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Answered by dryogeshkodhawade123

Answer:

In a triangle ABC, ANGLE B IS GREATER THAN ANGLE C. If AM is the bisector of angle BAC and AN is is perpendicular to BC. Prove that angle MAN = 1/2 ( angle B - angle C ).

Step-by-step explanation:

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in a triangle ABC, angleB > angleC. if AM is the bisector of angleBAC and AN is perpendicular to BC. prove that angleMAN = 1/2(angleB - angleC).​

Answers

in a triangle ABC, angleB > angleC. if AM is the bisector of angleBAC and AN is perpendicular to BC. prove that angleMAN = 1/2(angleB - angleC).