Question

In a triangle ABC, angleC=3*angleB=2(angleA+angleB). Find the three angle.​

Answer 1

Answer:

Step-by-step explanation:

According to the angle sum property

Angle A + angle B + angle C = 180

So, angle A + angle B = 180 - angle C... E1

Angle C = 2(angle A+ angle B)... Given

Angle C = 2(180 - angle C)... By Eq1

Angle C = 360 - 2angle C

3angle C = 360

Angle C = 120...... Eq2

Angle C = 3angleB

120 = 3angleB..... By Eq2

AngleB = 40

AngleA + angleB + angleC = 180

AngleA = 180 - (angleB + angleC)

AngleA = 180 - (40 + 120)

AngleA = 180 - 160

AngleA = 20

Hence, AngleA = 20

AngleB = 40

AngleC = 120

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Answer 2

Step-by-step explanation:

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