Question

In a triangle ABC angleC =3 angleB=2(angleA+angleB),find the measure of each one of angleA angleB angleC​

Answer 1

C=3B...(1)

3B=2(A+B)

or, 3B=2A+2B

or, B=2A...(2)

A+B+C=180(Angle Sum Property of a Triangle)...(3)

Substituting (1) in equation (3)

A+B+3B=180...(4)

Substituting (2) in equation (4)

A+2A+3(2A)=180

or,A+2A+6A=180

or,9A=180

or,A=20°.

B=2A=2(20)=40°.

C=3B=3(2A)=6A=6(20)=120°.

A->20°, B->40° and C->120°.

Answer 2

Hey mate here is your answer

3angleB = 2angleA + 2angleB
3angleB - 2angleB = 2angleA
angleB = 2angleA.........(1)

angleC = 3angleB
angleC = 3{2angleA} [from (1)]
angleC = 6angleA.......(2)

As, We know that
angle A + angle B + angle C = 180
angle A + 2angleA + 6angleA = 180
9angleA = 180
angleA = 180/9
angleA = 20

Therefore,
angleB = 2angleA = 2(20) = 40
angleC = 6angleA = 6(20) = 120.

Hope it will help you
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