Question

in a triangle ABC angleC=3angleB=2(angle A+ angle B )find the three angles

Answer 1

∠C = 3∠B = 2(∠A+∠B)

Since the sum of all the three interior angles of a triangle is 180°,

∠A +∠B + ∠C = 180°

∠A + ∠B = (180°-∠C)

∠C= 2(∠A +∠B)

∠C= 2(180°-∠C)

∠C=360°-2∠C

∠C= 120°

∠C= 3∠B

120°=3∠B

40°=∠B

Therefore, by using angle sum property of a triangle, ∠A= 20°

Hence, ∠A=20°

∠B= 40°

∠C=120°

Answer 2

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