Question

In a triangle ABC, BC = 5 cm, AC = 12 cm and AB = 13 cm. The length of the altitude drawn from B on AC is : (A) 4 cm (B) 5 cm (C) 6 cm (D) 7 cm

Answer 1

Answer:

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Step-by-step explanation:

Since 5

2

+12

2

=13

2

, the triangle is a right angled triangle with base BC=5cm, and height AC=12cm

Area of triangle =

2

1

× base × height =

2

1

×5×12=30 sq cm

Area of triangle remains same, if we consider any of the base and its corresponding height to calculate it.

So, if the altitude drawn from B to AC is BD, then

2

1

×12×BD=30 sq cm

∴BD=5cm

Answer 2

Answer:

5 cm

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