Question

In a triangle ABC, BC = AB. If angle BAC= 55°,find angle ACB.​

Answer 1

Answer:

Angle ACB is 70°.

Explanation:

We were told that BC is equal to AB in the triangle ABC.

Let's write the angles BAC and ACB as x and y, respectively.

We are given from the fact that BC = AB that angle BCA is likewise equal to x. This is thus because the angles across from equal sides in an isosceles triangle are also equal.

Let's now use the triangles' angle sum property. A triangle's total angles are always 180 degrees.

x + x + y = 180

When we simplify the equation, we get:

2x + y = 180

Since we are aware of the angle BAC's value of 55 degrees, we can enter x = 55 into the equation as follows:

2(55) + y = 180

110 + y = 180

Subtracting 110 from both sides, we get:

y = 180 - 110

y = 70

Therefore, angle ACB is 70°.

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