Question

in a triangle ABC, BE= 2EC and its area is 60 cm2​,then find the area of triangle AEC.

plesae answer urgently

Answer 1

According to the problem given ,

In ∆ABC , BE = 2EC,

Area of ∆ABC = 60 cm²

Let EC = x cm

BE = 2EC = 2x cm

BC = BE + EC

= 2x + x = 3x cm

Draw perpendicular AP to BC,

AP = h cm

Now ,

1 ) Area of ∆ABC = 60 cm²

=> ( BC × AP )/2 = 60

=> ( 3x * h ) = 120

=> h = 120/3x

=> h = ( 40/x ) cm -----( 1 )

2 ) Area of ∆AEC = ( EC × AP )/2

= ( x * h )/2

= [ x * (40/x) ]/2

= 40/2

= 20 cm²

Therefore ,

Area of ∆AEC = 20 cm²

•••••

Answer 2

Answer:

20cm^2

Step-by-step explanation:

Since

BC=BE+EC

2EC+EC

= 3EC

ar(tri.ABC)=60cm^2

ar(tri.AEC)=60/3=20cm^2