In a triangle ABC, bisectors of ∠B and ∠C intersect at point
P. Prove that ∠BPC = 90 + 1⁄2 ∠ BAC
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Hey!!!
Your Answer is the attachment above.
In the attachment bisectors of ∠B and ∠C intersect at point O. And in your question the point of intersection is P. So kindly replace O by in the whole solution. The solution is correct but I mistakenly marked the point of intersection as O.
Your Answer is the attachment above.
In the attachment bisectors of ∠B and ∠C intersect at point O. And in your question the point of intersection is P. So kindly replace O by in the whole solution. The solution is correct but I mistakenly marked the point of intersection as O.
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