In a triangle ABC BO AND CO are the bisector of angle ABC and angle ACB.if angle ABC=angle ACB and angle ABO equal to angle ACO show that angle CBO equal to angle BCO
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Given : In a triangle ABC BO and CO are the bisector of angle ABC and angle ACB . angle ABC=angle ACB
To Find : show that angle CBO equal to angle BCO
Solution:
Δ ABC
∠ABC = ∠ACB
Let say
∠ABC = ∠ACB = 2k
BO and CO are the bisector of ∠ABC and ∠ACB
=> ∠ABO = ∠CBO = (1/2)∠ABC = (1/2)2k = k
∠ACO = ∠BCO = (1/2)∠ACB = (1/2)2k = k
∠CBO = ∠BCO = k
QED
Hence proved
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