In a triangle ABC, CE is perpendicular to AB and BD to AC.. Prove AB x AE= AC x AD
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quadrilateral BEDC is a cyclic quadrilateral and
and AEB and ADC are two secants from outside point A
hence by tangent secant therom,
AB X AE = AC X AD
and AEB and ADC are two secants from outside point A
hence by tangent secant therom,
AB X AE = AC X AD
Answered by
1
Refer the attachment and...
Consider the △ABC,
So, we have to prove that, AB×AE=AC×AD
Now, consider the △ADB and △AEC,
∠A=∠A [common angle for both triangles]
∠ADB=∠AEC [both angles are equal to 90⁰]
△ADB∼△AEC
So, AB/AC=AD/AE
By cross multiplication we get,
AB×AE=AC×AD.
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