Math, asked by arunsinha2902, 9 months ago

In a triangle abc, cos(a+2b+3c/2)+cos(a-c/2)=

Answers

Answered by tushar9219
0

Step-by-step explanation:

In triangle a^2(cos^2b-cos^2c)+b^2(cos^2c-cos^2a)+c^2(cos^2a-cos ^2b) is equal to

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