Question

In a triangle ABC, cosec A (sin B cos C + cos B sin C) equals

Answer 1

$\implies$

Explanation:

We have,

cscA(sinBcosC+cos B sin C),

=cscAsin(B+C),

=cscAsin(π−A)...[as, in ΔABC,A+B +C=π],

=cscA⋅sinA,

=1.

Answer 2

Answer:

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