Question

In A triangle ABC, D and E are mid point of sides AB and AC and DE//BC then. DE is
equal to
​

Answer 1

Answer:

Given: D and E are mid points of AB and BC respectively. DF∥BC

Since, DF∥BC D is mid point of AB.

By converse of mid point theorem, F is mid point of AC.

Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,

EF∥AB or EF∥DB

Since, opposite sides are parallel to each other. Hence, DBEF is a parallelogram.