Math, asked by ss09891297, 7 months ago

In a triangle ABC, D and E are the points on sides AB and A C such that DE is parallel to BC.If AD : DB =2 : 3 and EC =9 cm, then the length of AC will be---

14 cm

6 cm

9/5 cm

15 cm

Answers

Answered by sanupeharkar
1

Answer:

triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that AD=8 cm, AB=12 cm and AE=12 cm.

Using the basic proportionality theorem, we have

AB

AD

=

AC

AE

=

BC

DE

AB

AD

=

AC

AE

12

8

=

AC

12

⇒8AC=12×12

⇒8AC=144

⇒AC=

8

144

=18

Now, CE=AC−AE=18−12=6 cm

Answered by vksaxena802
1

Answer:

6cm

us the answer of the question

Step-by-step explanation:

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