In a triangle ABC,D and E are two points on sides AB and BC, respectively such that AD : DB = 2: 3 and DE AC. If the area of triangle ADE is equal
to 18 cm , then what is the area (in cm?) of triangle ABC ?
Answers
Step-by-step explanation:
If you draw a line from A to E we have a triangle ADE.
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 y
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DE
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)= 45AC/DE
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)= 45AC/DEBut AC = (5/3) DE
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)= 45AC/DEBut AC = (5/3) DEArea of ABC = 45 (5/3) DE / DE
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)= 45AC/DEBut AC = (5/3) DEArea of ABC = 45 (5/3) DE / DE= 75 cm^2
If you draw a line from A to E we have a triangle ADE.Area of ADE = 18 cm^2Let AD = 2 yArea of ADE = (1/2)(ADxDE) =(1/2)(2y x DE) = 18y = 18/DEArea of ABC = 1/2((2+3)y)(AC)=(1/2)(5(18/DE)(AC)= 45AC/DEBut AC = (5/3) DEArea of ABC = 45 (5/3) DE / DE= 75 cm^2As a check, sketch several triangles and calculate the area of ADE.
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