in a triangle abc,d ,e and f are , respectively the mid points of bc,can and ac are 7 cm,8cmand 9 cm, respectively,find the perimeter
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Given: AB = 7 cm, BC = 8 cm, AC = 9 cm
In a ΔABC, D, E and F are, respectively,
the mid points of BC, CA and AB.
According to Midpoint Theorem:
EF = 1/2BC, DF = 1/2 AC and DE = 1/2 AB
Now, Perimeter of ∆DEF = DE + EF + DF = 1/2 (AB + BC + AC) = 1/2 (7 + 8 + 9) = 12
Perimeter of ΔDEF = 12 cm.
Answered by
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Answer:
the perimeter of ΔDEF is 12 cm.
Step-by-step explanation:
By using Midpoint Theorem, we get
Perimeter of ΔDEF = DE + EF + DF
=1/2AB+1/2BC+1/2AC
=1/2(7+8+9)
=24/2
=12cm
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